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BitNOT.au3
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2007-09-08
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207b
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10 lines
$x = BitNot(5)
#cs Comments:
Result is -6 because for 32-bit numbers
5 == 00000000000000000000000000000101 binary
-6 == 11111111111111111111111111111010 binary
and the first bit is signed
#ce